Hot Water

Johnws. The S.I unit for heat is the Joule (J) it takes 4,186 J of energy to raise the temp of 1 litre (= 1 kg) of water through 1degree C this is called the specific heat capacity of water.
Heat energy =mass specific heat capacity temp rise
H.e (kg) = mass (kg)x 4.186 (t2 -t1)deg c

Johnws, you need to know the initial temp to calculate.

the temp dif in a pressure situation is aprox 1deg f / 550ft

Johnws. The S.I unit for heat is the Joule (J) it takes 4,186 J of energy to raise the temp of 1 litre (= 1 kg) of water through 1degree C this is called the specific heat capacity of water.
Heat energy =mass specific heat capacity temp rise
H.e (kg) = mass (kg)x 4.186 (t2 -t1)deg c

Johnws, you need to know the initial temp to calculate.

the temp dif in a pressure situation is aprox 1deg f / 550ft

Thanks Robert for the reply, but this answers part of the question as this formula only takes the temperature to boiling point. Given that once the temperature is raised to 100 deg C (at atmospheric pressure) any additional energy will not raise the temperature further but will only convert the water to steam. Therefore how much extra energy is now required to convert this water to steam.

Look forward to your reply

The theoretical value for the latent heat of vaprization of water is 2.26 106 J/kg.
http://wug.physics.uiuc.edu/courses/phys113/summer01/Discussions/html/wk6/sol6_2.htm